How do you find the quotient of #(8k^2-6)div2k#?

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Answer 1 · 2017-10-22T21:11:48

You would need to divide #2k# into each of the terms of the expression #(8k^2-6)#

#(8k^2-6)/(2k)=4k-3/k#

#(8k^2-6)/(2k)=(8k^2)/(2k)-6/(2k)=4k-3/k#

Where we divided both integers by the #2# and

subtracted a #k^1# from both terms.

Since there was no #k# in the second term, the subtraction of #k^1# becomes a #k^-1# which is the same as #1/k^1 or 1/k#

To check, randomly make #k=3#:

#(8k^2-6)/(2k)=4k-3/k#

#(8(3)^2-6)/(2(3))=4(3)-3/(3)#

#(72-6)/6=12-1#

#11=11#