How do you find the quotient of #(b^2+6b+5)/(6b+6)div(b+5)#?

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Sep 20, 2017

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#1/6#

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The first step with algebraic fractions is to factorise wherever possible:

#(b^2 +6b+5)/(6b+6) color(blue)(div ((b+5))/1)#

#=((b+5)(b+1))/(6(b+1)) color(blue)(xx 1/((b+5)))" "larr# multiply by the reciprocal

#=(cancel((b+5))cancel((b+1)))/(6cancel((b+1))) xx 1/(cancel((b+5)))" "larr# cancel like factors

#=1/6#

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