How do you find the quotient of #(b^3+3b-9)div(b+5)# using long division?

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Answer 1 · 2017-04-30T06:30:47

The quotient is #=b^2-5b+28# and the remainder is #=-131#

Let's perform the long division

#color(white)(aaaa)##b^3##color(white)(aaaaaa)##3b-9##color(white)(aaaa)##|##b+5#

#color(white)(aaaa)##b^3+5b^2##color(white)(aaaaaa)##color(white)(aaaaa)##|##b^2-5b+28#

#color(white)(aaaa)##0-5b^2+3b#

#color(white)(aaaaaa)##-5b^2-25b#

#color(white)(aaaaaaaaaa)##0+28b+9#

#color(white)(aaaaaaaaaaaa)##+28b+140#

#color(white)(aaaaaaaaaaaaaaa)##0-131#

The quotient is #=b^2-5b+28# and the remainder is #=-131#