How do you find the quotient of #c^5/2divc^3/(6d^2)#?

1 Answer
Aug 31, 2017

See a solution process below:

Explanation:

We can rewrite the expression using this rule for dividing fractions:

#(color(red)(a)/color(blue)(b))/(color(green)(c)/color(purple)(d)) = (color(red)(a) xx color(purple)(d))/(color(blue)(b) xx color(green)(c))#

#c^5/2 -: c^3/(cd^2) => (color(red)(c^5)/color(blue)(2))/(color(green)(c^3)/color(purple)(6d^2)) => (color(red)(c^5) xx color(purple)(6d^2))/(color(blue)(2) xx color(green)(c^3)) => (cancel(color(red)(c^5))c^2 xx color(black)(cancel(color(purple)(color(purple)(6)))3d^2))/(cancel(color(blue)(2)) xx cancel(color(green)(c^3))) =>#

#3c^2d^2#