How do you find the quotient of #(k^2-5k-24)div(k-8)#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Binayaka C. Jan 28, 2017 Quotient is #(k+3)# Explanation: #(k^2-5k-24)/(k-8) or (k^2-8k+3k-24)/(k-8) or (k(k-8)+3(k-8))/(k-8) or(cancel((k-8))(k+3))/cancel((k-8))= (k+3)# [Ans] Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1556 views around the world You can reuse this answer Creative Commons License