# How do you find the quotient of (k+3)/(k+2)divk/(5k+10)?

Jun 3, 2017

#### Answer:

Alternate solution:

#### Explanation:

Take the reciprocal of the right side and multiply:

$\frac{k + 3}{k + 2} \times \frac{5 k + 10}{k}$

Factor out a $5$ from the right side:

$\frac{k + 3}{k + 2} \times \frac{5 \left(k + 2\right)}{k}$

Cancel $k + 2$:

$\frac{k + 3}{\cancel{k + 2}} \times \frac{5 \left(\cancel{k + 2}\right)}{k}$

You're left with:

$\frac{5 \left(k + 3\right)}{k}$

Distribute:

$\frac{5 k + 15}{k}$