How do you find the quotient of #(n^2+3n+10)div(n-1)# using long division? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Barney V. May 25, 2018 #n-4# and remainder of# 6/(n-1)# Explanation: #color(white)(..........)color(white)(............)n-4# #n-1|overline(n^2+3n+10)# #color(white)(............)ul(n^2-n)# #color(white)(......................)4n+10# #color(white)(......................)ul(4n+04)# #color(white)(..................................)6# #(n^2+3n+10) / (n-1) = n-4+6/(n-1)# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1631 views around the world You can reuse this answer Creative Commons License