How do you find the quotient of #(n^2+3n+10)div(n-1)# using long division?

1 Answer
May 25, 2018

Answer:

#n-4# and remainder of# 6/(n-1)#

Explanation:

#color(white)(..........)color(white)(............)n-4#
#n-1|overline(n^2+3n+10)#
#color(white)(............)ul(n^2-n)#
#color(white)(......................)4n+10#
#color(white)(......................)ul(4n+04)#
#color(white)(..................................)6#

#(n^2+3n+10) / (n-1) = n-4+6/(n-1)#