How do you find the quotient of #(p^3-4p^2+9)div(p-1)# using long division?

1 Answer
Barney V.
Sep 18, 2017

#p^2-3p+3 # and remainder#12/(p-1)#

Explanation:

#(p^3-4p^2+9)-:(p-1)#

#color(white)(..........)color(white)(..........)p^2-3p+3#
#p-1|overline(p^3-4p^2+0+9)#
#color(white)(............)ul(p^3-p^2)#
#color(white)(...............)-3p^2+0#
#color(white)(................)ul(-3p^2-3p)#
#color(white)(..................................)3p+9#
#color(white)(..................................)ul(3p-3)#
#color(white)(..........................................)12#

#(p^3-4p^2+9) / (p-1) = p^2-3p+3 # and remainder#12/(p-1)#

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