# How do you find the radius and center of a circle with the equation #5x^2+5y^2+60x+40y+215=0#?

##### 1 Answer

Center

#### Explanation:

From the give equation

we can see numbers that are divisible by 5.

We divide first by 5 to simplify the solution and the equation becomes

We now perform "completing the square method"

then add the required constants 36 and 16 on both sides of the equation

so that "Perfect Square Trinomials" will appear

and then

Convert now to "Center Radius Form"

We now have the Center (h, k) and Radius r by inspection

Center

graph of

graph{5x^2+5y^2+60x+40y+215=0[-20,5,-10,2]}

God bless...I hope the explanation is useful...