# How do you find the radius of a circle with the equation #x^2 + y^2 - 6x - 12y + 36 = 0#?

##### 1 Answer

Dec 16, 2015

Convert the equation to the general form for a circle

#### Explanation:

Given:

Group

Complete each of the

Rewrite as a sum of squared binomials equal to a square

This is the general form of a circle with center

graph{x^2+y^2-6x-12y+36=0 [-3.07, 9.42, 2.885, 9.13]}