# How do you find the range of each function given the domain: h(n)=3n^2-2n+2; {-1,0,1}?

##### 1 Answer
Nov 14, 2016

Just evaluate each of the $x$-values within the function.

$h \left(- 1\right) = 3 {\left(- 1\right)}^{2} - 2 \left(- 1\right) + 2 = 3 + 2 + 2 = 7$

$h \left(0\right) = 3 {\left(0\right)}^{2} - 2 \left(0\right) + 2 = 2$

$h \left(1\right) = 3 {\left(1\right)}^{2} - 2 \left(1\right) + 2 = 3 - 2 + 2 = 3$

Hence, the range is $\left\{2 , 3 , 7\right\}$.

Hopefully this helps!