Question

How do you find the range of each function given the domain: `h(n)=3n^2-2n+2; {-1,0,1}`?

Answer 1

Just evaluate each of the `x`-values within the function.

`h(-1) = 3(-1)^2 - 2(-1) + 2 = 3 + 2 + 2 = 7`

`h(0) = 3(0)^2 - 2(0) + 2 = 2`

`h(1) = 3(1)^2 - 2(1) + 2 = 3 - 2 + 2 = 3`

Hence, the range is `{2, 3, 7}`.

Hopefully this helps!