How do you find the range of #f(x)= 2/(3x-1)#?

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Answer 1 · 2018-03-21T16:34:10

The range is #RR -{0}#

The function is

#f(x)=2/(3x-1)#

To find the range, proceed as follows

Let #y=2/(3x-1)#

Therefore,

#y(3x-1)=2#

#y3x-y=2#

#3xy=(2+y)#

#x=(y+2)/(3y)#

Therefore,

As the denominator is #!=0#

#y!=0#

The range is #RR -{0}#

graph{2/(3x-1) [-10, 10, -5, 5]}