# How do you find the range of f(x)=3x+2 given the domain D={-2, 0, 2}?

$f \left(x\right) = 3 x + 2$
Domain $= \left\{- 2 , 0 , 2\right\}$
Range $= \left\{f \left(- 2\right) , f \left(0\right) , f \left(2\right)\right\}$
$= \left\{- 4 , 2 , 8\right\}$