# How do you find the range of  x^3 - 5 given D = {0, 1, 2, 3, 4}?

Jul 11, 2017

Im $f = \left\{f \left(0\right) , f \left(1\right) , f \left(2\right) , f \left(3\right) , f \left(4\right)\right\}$

#### Explanation:

$f \left(0\right) = {0}^{3} - 5 = - 5$
$f \left(1\right) = {1}^{3} - 5 = - 4$
$f \left(2\right) = {2}^{3} - 5 = 3$
$f \left(3\right) = {3}^{3} - 5 = 22$
$f \left(4\right) = {4}^{3} - 5 = 59$

$\left\{- 5 , - 4 , 3 , 22 , 59\right\}$