Question

How do you find the range of `y=4x²-5x+2`?

Answer 1

`y>=7/16`

Explanation:

We get

`y'(x)=8x-5`
`y''(x)=8`
So we get

`y(5/8)=4*25/64-25/8+2=7/16`

Since we have for `x=5/8` a minimum, so we get

`y>=7/16`