# How do you find the real and imaginary solutions of #x^4-8x^2=-16#?

##### 1 Answer

Nov 28, 2016

#### Answer:

#### Explanation:

Given:

#x^4-8x^2=-16#

Add

#0 = x^4-8x^2+16 = (x^2-4)^2 = (x-2)^2(x+2)^2#

So the solutions of the equation are