How do you find the rectangular equation for $r=sqrt5$ ?

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Answer 1 · 2016-08-15T11:47:01

$x^2+y^2=5$

From the conversion formula, #r(cos theta, sin theta)=(x, y), r

=sqrt(x^2+y^2).#,

Here, r = sqrt(x^2+y^2)sqrt 6#, and so,

$x^2+y^2=5$ .

How do you find the rectangular equation for r=sqrt5r=sqrt5?