How do you find the remainder for $(x^{3} + 10 x^{2} - 4) \div (x + 10)$ $(x^3+10x^2-4)div(x+10)$ ?

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Answer 1 · 2016-11-26T09:44:09

The remainder is $= - 4$ $=-4$

Let $f (x) = x^{3} + 10 x^{2} - 4$ $f(x)=x^3+10x^2-4$

To find the remainder when $f (x)$ $f(x)$ is divided by $(x - a)$ $(x-a)$

$f (x) = (x - a) \cdot q (x) + r$ $f(x)=(x-a)*q(x)+r$

when $x = a$ $x=a$

$f (a) = (a - a) \cdot q (a) + r$ $f(a)=(a-a)*q(a)+r$

$f (a) = 0 + r = r$ $f(a)=0+r=r$

Here, $f (x) = x^{3} + 10 x^{2} - 4$ $f(x)=x^3+10x^2-4$

and $a = - 10$ $a=-10$

So, $f (- 10) = - 1000 + 1000 - 4 = - 4$ $f(-10)=-1000+1000-4=-4$

How do you find the remainder for (x3+10x2−4)÷(x+10)(x^3+10x^2-4)div(x+10)?