How do you find the remainder when 2x^3-11x^2+17x-6 is divided by x+2?

1 Answer
Aug 29, 2016

The remainder is -100.

Explanation:

According to remainder theorem if a polynomial function f(x)=a_0+a_1x+a_2x^2+a_3x^3+....+a_nx^n is divided by (x-a), the remainder is given by f(a).

Hence, as f(x)=2x^3-11x^2+17x-6 is divided by x+2, the remainder will be given by

f(-2)=2×(-2)^3-11×(-2)^2+17×(-2)-6

= 2×(-8)-11×4+17×(-2)-6

= -16-44-34-6

= -100