How do you find the remainder when #2x^3-11x^2+17x-6# is divided by x+2?

1 Answer
Aug 29, 2016

The remainder is #-100#.

Explanation:

According to remainder theorem if a polynomial function #f(x)=a_0+a_1x+a_2x^2+a_3x^3+....+a_nx^n# is divided by #(x-a)#, the remainder is given by #f(a)#.

Hence, as #f(x)=2x^3-11x^2+17x-6# is divided by #x+2#, the remainder will be given by

#f(-2)=2×(-2)^3-11×(-2)^2+17×(-2)-6#

= #2×(-8)-11×4+17×(-2)-6#

= #-16-44-34-6#

= #-100#