How do you find the remainder when P(x) = x^4 - 9x^3 - 5x^2 - 3x+4 is divided by x+3?

Jan 13, 2016

292

Explanation:

To divide by (x + 3 ) you don't have to divide by (x + 3 ) . Using the

Remainder Theorem you just have to evaluate P( - 3 ).

$P \left(- 3\right) = {\left(- 3\right)}^{4} - 9 {\left(- 3\right)}^{3} - 5 {\left(- 3\right)}^{2} - 3 \left(- 3\right) + 4$

= 81 + 243 - 45 + 9 + 4

= 292

ie. remainder = 292