How do you find the remaining sides of a $45^{\circ} - 45^{\circ} - 90^{\circ}$ $45^circ-45^circ-90^circ$ triangle if the longest sides are each $8 \sqrt{2}$ $8sqrt2$ ?

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Answer 1 · 2017-03-04T23:03:35

both sides $= 8$ $= 8$

A $45^{\circ} - 45^{\circ} - 90^{\circ}$ $45^@ - 45^@ - 90^@$ triangle is in the ratio of $x : x : x \sqrt{2}$ $x:x:xsqrt(2)$

Since the longest side is $8 \sqrt{2}$ $8sqrt(2)$ , the other sides are $8$ $8$

How do you find the remaining sides of a 45∘−45∘−90∘45^circ-45^circ-90^circ triangle if the longest sides are each 8√28sqrt2?