# How do you find the restricted value for #(y^2-16)/(y^2+16)#?

##### 1 Answer

Feb 27, 2016

#### Answer:

The **domain** for

#### Explanation:

The **range** of the function will be

graph{(x^2-16)/(x^2+16) [-11.25, 11.25, -5.625, 5.625]}