How do you find the reverse distributive property of $3p - 6q + 12r$ ?

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Answer 1 · 2017-05-23T08:14:24

Divide out the highest common factor from the terms.
$3(p-2q+4r)$

This process would be the same as 'factorise'.

What factor do all of the terms contain?

That number would have been in front of a bracket and have been multiplied by all the terms in the bracket.

$color(red)(3)p -color(red)(6)q +color(red)(12)r" "larr$ all multiples of $3$

$=color(red)(3)(p-2q+4r)$

If you now apply the distributive property you will end up with the expression you started with.

How do you find the reverse distributive property of 3p - 6q + 12r 3p - 6q + 12r?