How do you find the reverse distributive property of # 3p - 6q + 12r#?

1 Answer
May 23, 2017

Answer:

Divide out the highest common factor from the terms.
#3(p-2q+4r)#

Explanation:

This process would be the same as 'factorise'.

What factor do all of the terms contain?

That number would have been in front of a bracket and have been multiplied by all the terms in the bracket.

#color(red)(3)p -color(red)(6)q +color(red)(12)r" "larr# all multiples of #3#

#=color(red)(3)(p-2q+4r)#

If you now apply the distributive property you will end up with the expression you started with.