How do you find the reverse distributive property of $t^{2} - t s + 3 t$ $t^2 - ts + 3t$ ?

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How do you find the reverse distributive property of $t^{2} - t s + 3 t$ $t^2 - ts + 3t$ ?

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Answer 1 · 2016-05-29T02:10:35

$t (t - s + 3)$ $t(t-s+3)$

Explanation:

First ask yourself what number or variable is present in each term. Here we see that $t$ $t$ occurs in each term. This is the variable that we can factor out of each term.

When we factor out $t$ $t$ we must then ask ourselves what we must multiply $t$ $t$ by to get the original problem.

What must we multiply $t$ $t$ by to get $t^{2}$ $t^2$ ?

That would be $t$ $t$ . So we start out with:

$t (t$ $t(t$

Then we ask ourselves what we multiply $t$ $t$ by to obtain $- t s$ $-ts$ .

That would be $- s$ $-s$ giving us:

$t (t - s$ $t(t-s$

Now for the last term we ask ourselves what we must multiply $t$ $t$ by to obtain $3 t$ $3t$ .

That of course would be $3$ $3$ giving us our answer of:

$t (t - s + 3)$ $t(t-s+3)$

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How do you find the reverse distributive property of $t^{2} - t s + 3 t$ $t^2 - ts + 3t$ ?

1 Answer

Explanation:

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How do you find the reverse distributive property of $t^{2} - t s + 3 t$ $t^2 - ts + 3t$ ?