Question

How do you find the roots of `4x^3-12x^2-x+3=0`?

Answer 1

`x=3` , `x=-1/2`, `x=1/2`

Explanation:

By partial collecting the first two term we have `4x^2(x-3)-(x-3)=0`

By total collecting we have `(x-3)(4x^2-1)=0` that can be decomposed as `(x-3)(2x+1)(2x-1)=0` and the roots are the ones above