How do you find the roots of $4x^3-12x^2-x+3=0$ ?

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Answer 1 · 2016-11-02T22:30:46

$x=3$ , $x=-1/2$ , $x=1/2$

By partial collecting the first two term we have $4x^2(x-3)-(x-3)=0$

By total collecting we have $(x-3)(4x^2-1)=0$ that can be decomposed as $(x-3)(2x+1)(2x-1)=0$ and the roots are the ones above

How do you find the roots of 4x^3-12x^2-x+3=04x^3-12x^2-x+3=0?