How do you find the roots of #4x^3-12x^2-x+3=0#?

1 Answer
Nov 2, 2016

Answer:

#x=3# , #x=-1/2#, #x=1/2#

Explanation:

By partial collecting the first two term we have #4x^2(x-3)-(x-3)=0#

By total collecting we have #(x-3)(4x^2-1)=0# that can be decomposed as #(x-3)(2x+1)(2x-1)=0# and the roots are the ones above