Question

How do you find the roots, real and imaginary, of `h(t)=-2t^2+16t -4` using the quadratic formula?

Answer 1

`a=-2,b=16,c=-4 ->x=(-b+- (sqrt(b^2-4ac)))/(2a) = (-16+- sqrt(16^2-4(-2)(-4)))/(2(-2)) = (-16+-sqrt224)/-4 = (-16+-4sqrt14)/-4 = 4+- -sqrt14`

Explanation:

List a,b,c and then substitute in to the quadratic formula then solve for x