# How do you find the roots, real and imaginary, of #y=-14 x^2 +18x +16-(x-3)^2 # using the quadratic formula?

##### 1 Answer

Aug 6, 2016

#### Answer:

#### Explanation:

The quadratic formula gives us the solutions to a quadratic equation of the form

#= -14x^2+18x+16-(x^2-6x+9)#

#= -14x^2+18x+16-x^2+6x-9#

#=-15x^2+24x+7#

Thus, we can now look for the roots as the solutions to

Plugging our values into the formula, we get

#=(-24+-sqrt(24^2-4(-15)(7)))/(2(-15))#

#=-(-24+-sqrt(576+420))/30#

#=(24+-sqrt(996))/30#

#=4/5+-sqrt(249)/15#

Thus, the roots of the given equation are