How do you find the roots, real and imaginary, of #y=-2(x - 2)^2-x^2+x + 12# using the quadratic formula?
You gotta re-write it in the proper form...
Remember that your quadratic equation is meant to find x for equations of form
So you start by:
...so now you have your coefficients a, b, and c for the quadratic equation.
Plug these in to the quadratic formula:
I get roughly
It's always good to check your answers by plugging these values for x into your original equation. You should get zero. (which you don't, with these values, exactly, because I've rounded off. But it's very close.)