How do you find the roots, real and imaginary, of #y= 2x^2 - 3x + 4+ 4(-x-1)^2 # using the quadratic formula?

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Answer 1 · 2018-01-04T14:51:42

no real solutions

#y=2x^2-3x+4+4(-x-1)^2#

#:.y=2x^2-3x+4+4(x^2+2x+1)#

#:.y=2x^2-3x+4+4x^2+8x+4#

#:.y=4x^2+5x+8#

#:.y=(-b+-sqrt(b^2-4ac))/(2a)#

#:.y=(-(5)+-sqrt((5)^2-4(6))(8))/(2(6))#

#:.y=(-5+-sqrt(-167))/(12)#

no real solutions.