# How do you find the roots, real and imaginary, of #y= 5x^2 - 2x-45 # using the quadratic formula?

##### 1 Answer

Jan 30, 2016

Since

#### Explanation:

When the quadratic equation is in the form -

#ax^2+bx+c=0#

Then its roots are given by

#x=(-b+-sqrt(b^2-(4ac)))/(2a)#

In this

If

If

In our case -

#(-2)^2-(4xx5xx-45)#

#4 - (-900)#

#4+900=904#

Since