# How do you find the roots, real and imaginary, of y=7x^2-2x + 6 using the quadratic formula?

Apr 11, 2016

$\frac{1 \pm 6.4 i}{7}$
$y = 7 {x}^{2} - 2 x + 6 = 0$
$D = {d}^{2} = {b}^{2} - 4 a c = 4 - 168 = - 164$ --> $d = \pm 12.80 \left(i\right)$
$x = - \frac{b}{2 a} \pm \frac{d}{2 a} = \frac{2}{14} \pm \frac{12.80 i}{14} = \frac{1 \pm 6.4 i}{7}$