How do you find the roots, real and imaginary, of #y=7x^2+4x + 6# using the quadratic formula?
Use the improved quadratic formula (Google, Yahoo Search)
y = 7x^2 + 4x + 6 = 0
D = d^2 = b^2 - 4ac = 16 - 168 = - 152
Since D < 0, there are no real roots. There are 2 complex roots.