How do you find the roots, real and imaginary, of y= x^2 +8x +16 using the quadratic formula?

Jun 9, 2018

As below.

Explanation:

$y = {x}^{2} + 8 x + 16$

$x = \frac{- b \pm \sqrt{{b}^{2} - 4 a c}}{2 a}$

$a = 1 , b = 8 , c = 16$

$x = \frac{- 8 \pm \sqrt{64 - 64}}{2}$

$x = - 4 , - 4$

This can be verifed as under ;

${x}^{2} + 8 x + 16 = {\left(x + 4\right)}^{2}$

$\therefore x = - 4 , - 4$