How do you find the roots, real and imaginary, of #y= x^2 +8x +16# using the quadratic formula?

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Answer 1 · 2018-06-09T09:44:24

As below.

#y = x^2 + 8x + 16#

#x = (-b +- sqrt(b^2 - 4ac)) / (2a)#

#a = 1, b = 8, c = 16#

#x = (-8 +- sqrt(64 - 64)) / 2#

#x = -4, -4#

This can be verifed as under ;

#x^2 + 8x + 16 = (x + 4)^2#

#:.x = -4,-4#