Question

How do you find the second derivative of `ln(4x)` ?

Answer 1

`f''(x) = -1/x^2`

Explanation:

`f(x) = ln(4x)`

`f'(x) = 1/(4x) * d/dx(4x)` Standard differential and Chain rule)

`f'(x) =1/(4x) *4 = 1/x`

`f''(x) = -1/x^2` (Power rule)