How do you find the second derivative of #y=2sin3x5sin6x#?
2 Answers
Feb 23, 2015
First find the first derivative using the chain rule.
Now take the derivative again to find the second derivative
Feb 23, 2015
Hello,
Answer
 First, you calculate the derivative :
#y' = 2 cos(3x)\times 3  5 cos(6x)\times 6# .
I used

You can simplify :
#y' = 6 cos(3x)  30 cos(6x)# . 
Now, you calculate the second derivative :
#y'' = 6 sin(3x) \times 3 + 30 sin(6x)\times 6#
I used
You can also simplify to obtain the result.