Question

How do you fInd the sine, cosine, and tangent of `(11pi)/4` radians?

Answer 1

`1/\sqrt2,\ -1/\sqrt2 \ \ &\ \ -1`

Explanation:

`\sin({11\pi}/4)=\sin(2\pi+{3\pi}/4)=\sin({3\pi}/4)=\sin(\pi-{\pi}/4)=\sin(\pi/4)=1/\sqrt2`

`\cos({11\pi}/4)=\cos(2\pi+{3\pi}/4)=\cos({3\pi}/4)=\cos(\pi-{\pi}/4)=-\cos(\pi/4)=-1/\sqrt2`

`\tan({11\pi}/4)=\tan(2\pi+{3\pi}/4)=\tan({3\pi}/4)=\sin(\pi-{\pi}/4)=-\tan(\pi/4)=-1`