How do you find the six trigonometric functions of #(19pi)/3# degrees?

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Answer 1 · 2018-03-17T05:23:35

As below.

To find the six trigonometric functions of #(19pi)/3#

We can write #(19pi)/3# as #(19pi)/3 - 6pi = (19pi - 18pi)/3 = pi/3#

Angle #pi/3# is in first quadrant where all the six trigonometric fiunctions are positive.

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#sin (pi/3) = sin 60 = sqrt3/2#

#csc (pi/3) = csc 60 = = 1/ sin(pi/3) = 2/sqrt3#

#cos (pi/3) = cos 60 = 1/2#

#sec (pi/3) = sec 60 = 1/cos (pi/3) = 2#

#tan (pi/3) = tan 60 = sqrt3#

#cot (pi/3) = cot 60 = 1/sqrt3#