How do you find the six trigonometric functions of #(-2pi)/3# degrees? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. May 25, 2015 Use the trig unit circle as proof. #sin ((-2pi)/3) = - sin (pi/3) = -(sqrt3)/2# #cos (-(2pi)/3) = - cos ((pi)/3) = -1/2# #tan ((-2pi)/3) = (sin/cos) = sqrt3# #cot ((-2pi)/3) = 1/(sqrt3) = (sqrt3)/3# #sec = 1/cos # = #csc = 1/sin # = Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 21275 views around the world You can reuse this answer Creative Commons License