How do you find the six trigonometric functions of 390 degrees? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. · EZ as pi Jun 3, 2015 #390° = 360°+30° = 30°# The ratios of 390 are the same as the ratios of 30°. Explanation: #sin 390 = sin (30 + 360) = sin 30 = 1/2# #cos 390 = cos (30 + 360) = cos 30 = sqrt3/2# #tan 390 = tan 30 = 1/sqrt3 = sqrt3/3# #cot 390 = 1/(tan 30) = sqrt3/1# #sec 390 = 1/cos 30 = 2/sqrt3# #csc 390 = 1/(sin 30) = 2/1# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 33652 views around the world You can reuse this answer Creative Commons License