How do you find the six trigonometric functions of #(-7pi)/4# degrees? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Nghi N. May 7, 2015 Trig unit circle: #sin (-7pi/4) = sin (pi/4 - 2pi) = sin (pi/4) = (sqr2)/2# (trig table) #cos (-7pi/4) = cos (pi/4 - 2pi) = cos (pi/4) = (sqr2)/2# (trig table) #tan (-7pi/4) = tan (pi/4) = ((sqr2)/2).(2/(sqr2)) = 1# #cot (-7pi/4) = 1# #sec (-7pi/4) = 2/(sqr2) = (2.sqr2)/2# #csc (-7pi/4) = (2.sqr2)/2# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 2192 views around the world You can reuse this answer Creative Commons License