How do you find the six trigonometric functions of #(-7pi)/4# degrees?

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Answer 1 · 2015-05-07T16:24:40

Trig unit circle:

#sin (-7pi/4) = sin (pi/4 - 2pi) = sin (pi/4) = (sqr2)/2# (trig table)

#cos (-7pi/4) = cos (pi/4 - 2pi) = cos (pi/4) = (sqr2)/2# (trig table)

#tan (-7pi/4) = tan (pi/4) = ((sqr2)/2).(2/(sqr2)) = 1#

#cot (-7pi/4) = 1#

#sec (-7pi/4) = 2/(sqr2) = (2.sqr2)/2#

#csc (-7pi/4) = (2.sqr2)/2#