How do you find the six trigonometric functions of #(7pi)/6# degrees?

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Answer 1 · 2015-05-07T16:14:25

Trig unit circle:

#sin ((7pi)/6) = sin (pi/6 + pi) = -sin (pi/6) = -1/2 # (trig table)

#cos ((7pi)/6) = cos (pi/6 + pi) = - cos pi/6 = -(sqr3)/2#

#tan ((7pi)/6) = (1/2).(2/(sqr3)) = 1/(sqr3) = (sqr3)/3#

#cot ((7pi)/6) = sqr3#

#sec (7pi/6) = -2/(sqr3) = (-2sqr3)/3#

#csc (pi/6) = -2#