How do you find the slant asymptote of #(2x-4)/(x^2-4)#?

1 Answer
Nov 27, 2015

Answer:

There is no slant asymptote if the polynomial in the denominator is a higher degree compared to the polynomial in the numerator.

Explanation:

Since #x^2# is a higher degree compared to #2x#, there is no slant asymptote.

There is a horizontal asymptote at #y=0# and two vertical asymptotes at #x=+-2#

hope that helps

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