Question

How do you find the slant asymptote of `a(x)=(2x^2-1) / (3x^3-2x+1)`?

Answer 1

There is no slant asymptote.

Explanation:

The degree of the numerator is `=2`

The degree of the denominator is `=3`

Therefore,

As the degree of the numerator is `<` than the degree of the denominator, there is no slant asymptote

graph{(2x^2-1)/(3x^3-2x+1) [-10, 10, -5, 5]}