How do you find the slant asymptote of # a(x)=(2x^2-1) / (3x^3-2x+1)#?

1 Answer
Jul 29, 2017

Answer:

There is no slant asymptote.

Explanation:

The degree of the numerator is #=2#

The degree of the denominator is #=3#

Therefore,

As the degree of the numerator is #<# than the degree of the denominator, there is no slant asymptote

graph{(2x^2-1)/(3x^3-2x+1) [-10, 10, -5, 5]}