# How do you find the slant asymptote of #y = (3x^2 + 2x - 3 )/( x - 1)#?

##### 1 Answer

Nov 14, 2016

#### Answer:

The slant asymptote is

#### Explanation:

The degree of the numerator

Just do a long division

Therefore, the slant asymptote is

graph{(y-(3x^2+2x-3)/(x-1))(y-3x-5)=0 [-32.04, 32.92, -9.17, 23.3]}