How do you find the slope and one point on the line that each point-slope equation represents for y=3+2(x-1)?

Apr 6, 2015

Gradient is $2$ point is $\left(1 , 3\right)$

All you really got to do is to arrange that equation: $y = 3 + 2 \left(x - 1\right)$ in the form below

$y - {y}_{0} = m \left(x - {x}_{0}\right)$

where $m$ is the gradient and the point is $\left({x}_{0} , {y}_{0}\right)$

$\implies y - 3 = 2 \left(x - 1\right)$

Hence, it's easy to see that $m = 2$ and the point is $\left(1 , 3\right)$

Apr 6, 2015

Point-slope equation:

$\left(y - {y}_{1}\right) = m \left(x - {x}_{1}\right)$

$y = 3 + 2 \left(x - 1\right)$

$y - 3 = 2 \left(x - 1\right)$

${y}_{1} = 3$ and ${x}_{1} = 1$

The point is (1,3) and the slope ($m$) is 2.