How do you find the slope given (11, -2) and (2, -2)?

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Answer 1 · 2018-04-19T16:02:37

See below..

Slope of a line #m# passing through #(x_1,y_1)# and #(x_2,y_2)# is given by

#" "m=(y_2-y_1)/(x_2-x_1)#

Plugging in the given values we get

#" "m=(11-2)/(-2+2)#

which is undefined, and this gives rise to a special case. The line with undefined slope is a line parallel to the #y#-axis.

Also, slope is #tan theta#. When #tan theta=#undefined, then #theta=pi/2#, which is parallel to #y#-axis.

Answer 2 · 2018-04-19T16:33:54

Nothing, undefined, or #0#

We can find the slope or gradient using:

#(Deltay)/(Deltax)# Where #Delta# means the 'change in...'

Remembering the coordinates are #(x,y)#

#11 -> 2# we have to #-9#

#-2 -> -2 # we do nothing.

Therefore using #(Deltay)/(Deltax)# -> #0/-9 #-> which is nothing, or undefined.

As dividing by #0#, or multiplying by #0# gives nothing.