How do you find the slope given (8,17) and (14,-17)?

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How do you find the slope given (8,17) and (14,-17)?

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Answer 1 · 2016-07-13T11:03:04

$- \frac{17}{3}$ $-17/3$

Explanation:

Slope (gradient) $\to \frac{change in the y-axis}{change in the x-axis}$ $->("change in the y-axis")/("change in the x-axis")$

Think of the gradient of a hill.

Let Point 1 $\to P_{1} \to (x_{1}, y_{1}) = (8, 17)$ $->P_1->(x_1,y_1) = (8,17)$

Let Point 2 $\to P_{2} \to (x_{2}, y_{2}) = (14, - 17)$ $->P_2->(x_2,y_2)=(14,-17)$

Let the slope (gradient) be $m$ $m$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$\to \frac{change in the y-axis}{change in the x-axis} \to \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ $->("change in the y-axis")/("change in the x-axis") ->(y_2-y_1)/(x_2-x_1)$

$\Rightarrow m = \frac{- 17 - 17}{14 - 8} = \frac{- 34}{6}$ $=>m" "=" "(-17-17)/(14-8)" "=" "(-34)/6$

But $- \frac{34}{6} = - \frac{34 \div 2}{6 \div 2} = - \frac{17}{3}$ $-34/6" " =" " -(34-:2)/(6-:2)" " =" " -17/3$

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How do you find the slope given (8,17) and (14,-17)?

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