# How do you find the slope of (2.78,10) and (3.05,12)?

May 26, 2015

Given two points $\left({x}_{0} , {y}_{0}\right)$ and $\left({x}_{1} , {y}_{1}\right)$, the slope of a line through them is (change in $y$) / (change in $x$).

That is:

slope = $\frac{{y}_{1} - {y}_{0}}{{x}_{1} - {x}_{0}}$

In your case we have ${x}_{0} = 2.78$, ${y}_{0} = 10$, ${x}_{1} = 3.05$ and ${y}_{1} = 12$.

So slope = $\frac{12 - 10}{3.05 - 2.78}$

$= \frac{2}{0.27} = \frac{200}{27} = 7. \dot{4} 0 \dot{7}$