How do you find the slope of (2.78,10) and (3.05,12)?

1 Answer
George C.
May 26, 2015

Given two points #(x_0, y_0)# and #(x_1, y_1)#, the slope of a line through them is (change in #y#) / (change in #x#).

That is:

slope = #(y_1 - y_0) / (x_1 - x_0)#

In your case we have #x_0 = 2.78#, #y_0 = 10#, #x_1 = 3.05# and #y_1 = 12#.

So slope = #(12 - 10) / (3.05 - 2.78)#

#= 2/0.27 = 200/27 = 7.dot(4)0dot(7)#

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