How do you find the slope of #2y+3x=-6#?

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Answer 1 · 2015-05-09T22:50:30

Write the equation in slope-intercept form: #y=mx+b#, where #m# is the slope, and #b# is the y-intercept.

#2y+3x=-6#

Subtract #3x# from both sides.

#2y=-3x-6#

Divide both sides by #2#.

#y=(-3x)/(2)-(6)/(2)# =

#y=-3/2x-3#.

The slope, #m#, is #-3/2x# .