How do you find the slope of #(3,2), (5,6)#?

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Answer 1 · 2016-11-23T17:28:58

2

The slope is the gradient and for cords#" "(x_1,y_1)" "#&#" "(x_2,y_2)#

#m=(y_2-y_1)/(x_2-x_1)#

in this case

#m=(6-2)/(5-3)=4/2=2#

Answer 2 · 2016-11-23T17:30:57

#m=(y_2-y_1)/(x_2-x_1)=2#.

Slope, #m#, is defined as the change in #y# divided by the change in #x#, or #m=(Deltay)/(Deltax)=(y_2-y_1)/(x_2-x_1)=(6-2)/(5-2)=4/2=2#.